Homework 4 was released today and is now available on the course web page. So begins rankmaniac 2011... I look forward to seeing all the crazy things you do.

(Remember not to get me in too much trouble though!)

I will be willing to post links to peoples pages from the course website if so desired. There is a limit of 1 page per group that I will link to though.

## Wednesday, January 26, 2011

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@Adam: Are the teams allowed to request changes to the link that you post on the course website?

ReplyDelete@Raga: No. You get one request per team, and they will go as a list of links underneath the HW4 link on the page. The ordering will be FCFS.

ReplyDelete@Adam, here's our team's link:

ReplyDeletehttp://www.ugcs.caltech.edu/~kratsg/RankManiac2011

Is there anyone out there still looking for a group? I need one.

ReplyDelete-Isaac Sheff

@Isaac, if nobody else has an available group, my group (2 people) would be willing to have you.

ReplyDeleteMuch obliged, Rank. Who are you, and how do I contact you by more reasonable means? I have some ideas . . .

ReplyDeleteYuehua (Fred) and Scott's link

ReplyDeletehttp://rankmaniac2011.caltech.edu/

@Isaac, have you decided to join Rank yet?

ReplyDeleteI am also looking for a group, contact me via bchen3@caltech.edu if you are interested.

Dave asked an important question related to problem 2 on HW4 under the Lecture 6 post. Be sure to check his question and my response.

ReplyDeleteSorry, Rank is me (Giordon).

ReplyDeleteDave seems like he would be interested in working with you Isaac.

Hi Prof. Wierman, could you please change our link name to "Fred and Scott" instead of the current "Yuehua and Scott"? Thanks!

ReplyDeleteFor problem number 2, how many approximations can we make? I know it says that n is a large number. Does this mean that we can take it such that 1/n ~ 1/(n+1)? Or that 1/n ~ 0 ? How exact does this problem need to be when we're calculating such things?

ReplyDeleteThe more precise we have to be, it seems the harder it is to actually find an answer for r~ in terms of r.

rankmaniac2011.com - registered on Jan 26, 2011.

ReplyDeleteGoDaddy suspended its registration due to spam complaints. Whoever registered it now has to pay $50 to get it back!

http://www.whois.net/whois/rankmaniac2011.com

@Adam,

ReplyDeleteHere's the link for Isaac and Bo:

http://rank-maniac-2011.appspot.com/

Wen-Hao link:

ReplyDeletehttp://www.rankmaniac2011.tk/

Thanks

Claudia & Ben's link:

ReplyDeletehttp://www.rankmaniac2011.caltech.edu/